PDF Rendering Problem

I started to develop a pdf rendering problem when switching to my new Dell
830 notebook. The same matrix type report now have text running over cell
boundary lines - it never happened before. I even tried to change the
resolution back to 1024x768 - using 1920x1200 now - it didnt have any affect.
I use Adobe 8 and SQL Reporting Services as part of the SQL 2005 Express
edition, Windows XP Professional SP2.On Jul 24, 6:34 am, Dawie <Da...@.discussions.microsoft.com> wrote:
> I started to develop a pdf rendering problem when switching to my new Dell
> 830 notebook. The same matrix type report now have text running over cell
> boundary lines - it never happened before. I even tried to change the
> resolution back to 1024x768 - using 1920x1200 now - it didnt have any affect.
> I use Adobe 8 and SQL Reporting Services as part of the SQL 2005 Express
> edition, Windows XP Professional SP2.
If you are not using the SP2 version of SQL Server 2005 Express
Edition w/Advanced Services, this might help. Also, if there are
updates available for Adobe Reader, you might want to look into those.
Sorry that I could not be of greater assistance.
Regards,
Enrique Martinez
Sr. Software Consultant

PDF Not begin handled by FireFox

When I use the Webservice Render method for a PDF, the PDF shows perfectly
in IE but in FireFox it dumps the text of the pdf instead of rendering it...
Any ideas?
Tim Philomeno
tphilomeno@.sparling.comWhat does your FireFox do when you open other PDFs?
--
Floyd
"Tim Philomeno" <tphilomeno@.sparling.com> wrote in message
news:OvsscidnFHA.2472@.tk2msftngp13.phx.gbl...
> When I use the Webservice Render method for a PDF, the PDF shows perfectly
> in IE but in FireFox it dumps the text of the pdf instead of rendering
> it...
> Any ideas?
> Tim Philomeno
> tphilomeno@.sparling.com
>|||If I open a PDF from a local drive or the internet, it works perfectly...
Tim
"Floyd Burger" <mrlements@.community.nospam> wrote in message
news:%23exPxUenFHA.708@.TK2MSFTNGP09.phx.gbl...
> What does your FireFox do when you open other PDFs?
> --
> Floyd
> "Tim Philomeno" <tphilomeno@.sparling.com> wrote in message
> news:OvsscidnFHA.2472@.tk2msftngp13.phx.gbl...
>> When I use the Webservice Render method for a PDF, the PDF shows
>> perfectly in IE but in FireFox it dumps the text of the pdf instead of
>> rendering it...
>> Any ideas?
>> Tim Philomeno
>> tphilomeno@.sparling.com
>|||It could be that FireFox is observing the file extension to determine that
it needs to pass the file to Acrobat vs. the mime type.
"Tim Philomeno" <tphilomeno@.sparling.com> wrote in message
news:OvsscidnFHA.2472@.tk2msftngp13.phx.gbl...
> When I use the Webservice Render method for a PDF, the PDF shows perfectly
> in IE but in FireFox it dumps the text of the pdf instead of rendering
it...
> Any ideas?
> Tim Philomeno
> tphilomeno@.sparling.com
>sql

PDF Full Text Search

Hi all,

I have a table configured to support Full-Text Search and in this tables a column stores documents of three types, Word, Excel and PDF. Everything works fine with Word and Excel documents.

In order to search PDF documents I've installed "IFilter 5.0", which is published in Acrobat's page, but nothing. What else should I do, is there any other solution?

I've read that I can create a particular filter, so the question is where can find information about creating customized filters? But first, is it a good business to create a new filter?

Thanks in advance.Dear mvargasp,
I have a problem about FTS. I think you could help me...
I wrote to forum but nobody reply to me...

I need your help,
Thanks alot
Yusuf
--------
I've a problem. I'm inexperienced about FTS.
I have a TEXT datatype field in my table and I store MS Word documents.

I want to do full text search on this TEXT datatype field.
So I build catalog and run

"Select * from table where Contains (textfield,'Yusuf')" sql in analyzer.

but null value returns. however I know the table has 3 records.

Anyway, I insert a varchar field in the table and edit my fts catalog.
and then insert 3 records in the table.than rebuild catalog and I try
"Select * from table where Contains (varcharfield,'Yusuf')"
this sql returns true records.

I know that I can FTS in TEXT datatype field but I can't. I don't know why.
I need your help.
thanks alot

Yusuf|||Hi Yusuf,

It seems that you have created a catalog and rebuild it then, but you have not populate it. So What you must do after you create or rebuild a catalog is to populate it. I order to do so, you must right click your catalog in the Enterprise Manager and then click Populate.

After this the FTS must work.

God Bless.

PDF Format Issues

My report was beautiful until I put groups around my two tables... actually
at first it looked fine... then I started changing text box sizes etc...
suddenly every second page in my report is blank... not in the viewer... when
I export to PDF... anyone know a RS exorcist?A bit silly to reply to my own post... but maybe someone else will run into
this problem... and it can be frustrating so here's how I fixed my problem...
1st off... a "page" in html isn't exactly the same size as a page in PDF...
a page in PDF has to be the same size as your paper... or less... I don't
know if html even has an exact page size limit... NEways...
The report designer in Visual Studio will increase your page size... if you
try to move a control outside of the space you have set... a pretty annoying
feature if you ask me... given that you usually want a page size to be
exactly the same forever... and sometimes you are playing with a long text
box, and you might not see the part off to the side increasing your page
width.
Does anyone know... is there a way to lock the page size?
"MER78" wrote:
> My report was beautiful until I put groups around my two tables... actually
> at first it looked fine... then I started changing text box sizes etc...
> suddenly every second page in my report is blank... not in the viewer... when
> I export to PDF... anyone know a RS exorcist?

PDF Export / Bold Text / Underline text decoration

I'm having a problem when I have a text item in a table - the text is bold
and underlined; preview/print preview looks fine; but when I export the
report to PDF, the underline extends beyond the text to the right. If the
text is normal weight, the underline is fine. Is this a known issue? (maybe
fixed w/ RS SP2' - I looked at the bug list and saw some PDF fixes, but not
for this specific problem).
ThanksSome more information on this problem:
Any font specified as bold, bolder, extra-bold, etc. with the text
decoration set to Underline ... looks fine in designer / web preview whether
in a table or by itself in a textbox - but when exported to PDF, the bold
disappears (underline stays, though - but even this is a problem - the
underline extends to the right beyond the text) - maybe if the bold was
really bold, it would be the correct width for the text.
For example:
--
Instead of
For example:
--
I suspect this is a bug w/ the PDF export. Any ideas on possible workarounds?
TIA
"JKirst" wrote:
> I'm having a problem when I have a text item in a table - the text is bold
> and underlined; preview/print preview looks fine; but when I export the
> report to PDF, the underline extends beyond the text to the right. If the
> text is normal weight, the underline is fine. Is this a known issue? (maybe
> fixed w/ RS SP2' - I looked at the bug list and saw some PDF fixes, but not
> for this specific problem).
> Thanks
>|||JKirst,
I had a similar issue with text decoration in the export to PDF, but in my
case the underline disappeared altogether. Through an incident call with MS,
they confirmed there is a bug related to the calculation of the text
decoration and do not have a scheduled fix.
I did discover a work around in my case. It appears that if you have a text
box (whether in a table or just stand alone) that has its CanGrow property
set to true, but the height defined smaller than the defined font size and
text decorations, the text decorations may not render or render improperly if
the data text box does not wrap to 2 or more lines. To fix this, simply
define your textbox's starting height to be greater than the font size with
all potential text decorations applied.
"JKirst" wrote:
> Some more information on this problem:
> Any font specified as bold, bolder, extra-bold, etc. with the text
> decoration set to Underline ... looks fine in designer / web preview whether
> in a table or by itself in a textbox - but when exported to PDF, the bold
> disappears (underline stays, though - but even this is a problem - the
> underline extends to the right beyond the text) - maybe if the bold was
> really bold, it would be the correct width for the text.
> For example:
> --
> Instead of
> For example:
> --
> I suspect this is a bug w/ the PDF export. Any ideas on possible workarounds?
> TIA
> "JKirst" wrote:
> > I'm having a problem when I have a text item in a table - the text is bold
> > and underlined; preview/print preview looks fine; but when I export the
> > report to PDF, the underline extends beyond the text to the right. If the
> > text is normal weight, the underline is fine. Is this a known issue? (maybe
> > fixed w/ RS SP2' - I looked at the bug list and saw some PDF fixes, but not
> > for this specific problem).
> >
> > Thanks
> >
> >

PATINDEX to Retrieve data from text field

I am trying to retrieve the data from a table that has text datatype. I just
need to
pull 5 digit numeric value from there which can later be matched with
another table
that has this 5 digit key. Let us assume the table name is Tab1. There are
two
columns col1 containing RecordId and col2 containing text data. I have
created some dummy data to explain my needs:
Col1 Col2
1001 @.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC INC.@.SOMETHING
1002 @.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF INC.@.SOMETHING
1003 @.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI INC.@.ANYTHING
1004 @.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM INC.@.ANYTHING
1005 @.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING
1006 @.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING
1007 @.:92A:CUST8@.ANYTHING
If I use the following Query which needs to be tuned up to get the right
resultset:
SELECT SUBSTRING(col2, PATINDEX('%@.:97_:%', col2)+14, 5)
from tab1
where PATINDEX('%@.:97_:%', col2) > 0
I get the following results: The top two results are correct but others are
not.
col1 col2
-- --
1001 11221
1002 11229
1003 1233@.
1004 333@.C
1005 IENT
1006 AME I
I need the following resultset from the above data:
Col1 Col2
-- --
1001 11221
1002 11229
1003 11233
1004 11333
1005 22333
Col1 Id 1006 does not have the 5 digit numeric value so it is not required
in the
resultset. Id 1007 does not have :97_C: so this is also not required in the
resultset
too. I will appreciate your help. Thanks in advance. Fraz
Fraz
Look at this example helps you
CREATE FUNCTION dbo.CleanChars
(@.str VARCHAR(8000), @.validchars VARCHAR(8000))
RETURNS VARCHAR(8000)
BEGIN
WHILE PATINDEX('%[^' + @.validchars + ']%',@.str) > 0
SET @.str=REPLACE(@.str, SUBSTRING(@.str ,PATINDEX('%[^' + @.validchars +
']%',@.str), 1) ,'')
RETURN @.str
END
GO
CREATE TABLE sometable
(namestr VARCHAR(20) PRIMARY KEY)
INSERT INTO sometable VALUES ('AB-C123')
INSERT INTO sometable VALUES ('A,B,C')
SELECT namestr,
dbo.CleanChars(namestr,'A-Z 0-9')
FROM sometable
drop table sometable
drop function dbo.CleanChars
"Fraz" <Fraz@.discussions.microsoft.com> wrote in message
news:B964C72E-D1A4-4906-A105-E1D87A2F29D6@.microsoft.com...
> I am trying to retrieve the data from a table that has text datatype. I
just
> need to
> pull 5 digit numeric value from there which can later be matched with
> another table
> that has this 5 digit key. Let us assume the table name is Tab1. There are
> two
> columns col1 containing RecordId and col2 containing text data. I have
> created some dummy data to explain my needs:
> Col1 Col2
> 1001 @.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
INC.@.SOMETHING
> 1002 @.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
INC.@.SOMETHING
> 1003 @.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI INC.@.ANYTHING
> 1004 @.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM INC.@.ANYTHING
> 1005 @.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING
> 1006 @.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING
> 1007 @.:92A:CUST8@.ANYTHING
> If I use the following Query which needs to be tuned up to get the right
> resultset:
> SELECT SUBSTRING(col2, PATINDEX('%@.:97_:%', col2)+14, 5)
> from tab1
> where PATINDEX('%@.:97_:%', col2) > 0
> I get the following results: The top two results are correct but others
are
> not.
> col1 col2
> -- --
> 1001 11221
> 1002 11229
> 1003 1233@.
> 1004 333@.C
> 1005 IENT
> 1006 AME I
> I need the following resultset from the above data:
> Col1 Col2
> -- --
> 1001 11221
> 1002 11229
> 1003 11233
> 1004 11333
> 1005 22333
> Col1 Id 1006 does not have the 5 digit numeric value so it is not required
> in the
> resultset. Id 1007 does not have :97_C: so this is also not required in
the
> resultset
> too. I will appreciate your help. Thanks in advance. Fraz
|||Uri: Thanks for your valuable input. This is a nice function which I am
trying to see if it can fit in my needs. If you could help little more by
showing how I can check to see the 5 digit numbers (11233) between this data
@.:97B:/XX022511233@.CLIENT. The position is always not the same. So by getting
@.:97_: we can get first position and by next "@." we can get second position.
Now I know that my data is in between first and second position and by using
RIGHT function I can get the 5 right digits. Thanks again...Fraz
"Uri Dimant" wrote:

> Fraz
> Look at this example helps you
> CREATE FUNCTION dbo.CleanChars
> (@.str VARCHAR(8000), @.validchars VARCHAR(8000))
> RETURNS VARCHAR(8000)
> BEGIN
> WHILE PATINDEX('%[^' + @.validchars + ']%',@.str) > 0
> SET @.str=REPLACE(@.str, SUBSTRING(@.str ,PATINDEX('%[^' + @.validchars +
> ']%',@.str), 1) ,'')
> RETURN @.str
> END
> GO
> CREATE TABLE sometable
> (namestr VARCHAR(20) PRIMARY KEY)
> INSERT INTO sometable VALUES ('AB-C123')
> INSERT INTO sometable VALUES ('A,B,C')
> SELECT namestr,
> dbo.CleanChars(namestr,'A-Z 0-9')
> FROM sometable
>
> drop table sometable
> drop function dbo.CleanChars
> "Fraz" <Fraz@.discussions.microsoft.com> wrote in message
> news:B964C72E-D1A4-4906-A105-E1D87A2F29D6@.microsoft.com...
> just
> INC.@.SOMETHING
> INC.@.SOMETHING
> are
> the
>
>
|||Hi Fraz,
On Thu, 14 Apr 2005 06:30:05 -0700, Fraz wrote:
(snip)
>I need the following resultset from the above data:
>Col1 Col2
>-- --
>1001 11221
>1002 11229
>1003 11233
>1004 11333
>1005 22333
(snip)
Try the following (note: I added a test case to check that I return the
five digits preceding "@." AFTER the "@.:97_:" marker, not simply the
first five digits followed by "@.").
-- Set up test table and fill it with some rows
create table tab1 (col1 int not null primary key, col2 varchar(200))
go
insert into tab1
select 1001, '@.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
INC.@.SOMETHING'
union all
select 1002, '@.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
INC.@.SOMETHING'
union all
select 1003, '@.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI
INC.@.ANYTHING'
union all
select 1004, '@.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM
INC.@.ANYTHING'
union all
select 1005, '@.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING'
union all
select 1006, '@.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING'
union all
select 1007, '@.:92A:CUST8@.ANYTHING'
union all
select 1008, '@.:92A:CUST44444@.:97B:/XX022511233@.CLIENT NAME IS GHI
INC.@.ANYTHING'
go
-- Here's the code:
SELECT col1,
SUBSTRING(col2,
PATINDEX('%[0-9][0-9][0-9][0-9][0-9]@.%',
SUBSTRING(col2,
PATINDEX('%@.:97_:%', col2),
LEN(col2)))
+ PATINDEX('%@.:97_:%', col2)
- 1,
5)
FROM tab1
WHERE col2 LIKE '%@.:97_:%[0-9][0-9][0-9][0-9][0-9]@.%'
go
-- Done. Now cleanup.
drop table tab1
go
Best, Hugo
(Remove _NO_ and _SPAM_ to get my e-mail address)
|||Hello Hugo,
Your code has worked excellently. Most of the 5 digit numbers were correct
except for a few records that were very long and numbers were not correct. I
have dealt with it separately. Thanks a lot for your help. Cheers... Fraz
"Hugo Kornelis" wrote:

> Hi Fraz,
> On Thu, 14 Apr 2005 06:30:05 -0700, Fraz wrote:
> (snip)
> (snip)
> Try the following (note: I added a test case to check that I return the
> five digits preceding "@." AFTER the "@.:97_:" marker, not simply the
> first five digits followed by "@.").
> -- Set up test table and fill it with some rows
> create table tab1 (col1 int not null primary key, col2 varchar(200))
> go
> insert into tab1
> select 1001, '@.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
> INC.@.SOMETHING'
> union all
> select 1002, '@.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
> INC.@.SOMETHING'
> union all
> select 1003, '@.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI
> INC.@.ANYTHING'
> union all
> select 1004, '@.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM
> INC.@.ANYTHING'
> union all
> select 1005, '@.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING'
> union all
> select 1006, '@.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING'
> union all
> select 1007, '@.:92A:CUST8@.ANYTHING'
> union all
> select 1008, '@.:92A:CUST44444@.:97B:/XX022511233@.CLIENT NAME IS GHI
> INC.@.ANYTHING'
> go
> -- Here's the code:
> SELECT col1,
> SUBSTRING(col2,
> PATINDEX('%[0-9][0-9][0-9][0-9][0-9]@.%',
> SUBSTRING(col2,
> PATINDEX('%@.:97_:%', col2),
> LEN(col2)))
> + PATINDEX('%@.:97_:%', col2)
> - 1,
> 5)
> FROM tab1
> WHERE col2 LIKE '%@.:97_:%[0-9][0-9][0-9][0-9][0-9]@.%'
> go
>
> -- Done. Now cleanup.
> drop table tab1
> go
>
> Best, Hugo
> --
> (Remove _NO_ and _SPAM_ to get my e-mail address)
>
|||On Fri, 22 Apr 2005 14:21:03 -0700, Fraz wrote:

>Hello Hugo,
>Your code has worked excellently. Most of the 5 digit numbers were correct
>except for a few records that were very long and numbers were not correct. I
>have dealt with it separately. Thanks a lot for your help. Cheers... Fraz
Hi Fraz,
Good to hear that it worked for you. Thanks for reporting back!
Best, Hugo
(Remove _NO_ and _SPAM_ to get my e-mail address)

PATINDEX to Retrieve data from text field

I am trying to retrieve the data from a table that has text datatype. I just
need to
pull 5 digit numeric value from there which can later be matched with
another table
that has this 5 digit key. Let us assume the table name is Tab1. There are
two
columns col1 containing RecordId and col2 containing text data. I have
created some dummy data to explain my needs:
Col1 Col2
1001 @.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC INC.@.SOMETHI
NG
1002 @.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF INC.@.SOMETHING
1003 @.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI INC.@.ANYTHING
1004 @.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM INC.@.ANYTHING
1005 @.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING
1006 @.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING
1007 @.:92A:CUST8@.ANYTHING
If I use the following Query which needs to be tuned up to get the right
resultset:
SELECT SUBSTRING(col2, PATINDEX('%@.:97_:%', col2)+14, 5)
from tab1
where PATINDEX('%@.:97_:%', col2) > 0
I get the following results: The top two results are correct but others are
not.
col1 col2
-- --
1001 11221
1002 11229
1003 1233@.
1004 333@.C
1005 IENT
1006 AME I
I need the following resultset from the above data:
Col1 Col2
-- --
1001 11221
1002 11229
1003 11233
1004 11333
1005 22333
Col1 Id 1006 does not have the 5 digit numeric value so it is not required
in the
resultset. Id 1007 does not have :97_C: so this is also not required in the
resultset
too. I will appreciate your help. Thanks in advance. FrazFraz
Look at this example helps you
CREATE FUNCTION dbo.CleanChars
(@.str VARCHAR(8000), @.validchars VARCHAR(8000))
RETURNS VARCHAR(8000)
BEGIN
WHILE PATINDEX('%[^' + @.validchars + ']%',@.str) > 0
SET @.str=REPLACE(@.str, SUBSTRING(@.str ,PATINDEX('%[^' + @.validchars +
']%',@.str), 1) ,'')
RETURN @.str
END
GO
CREATE TABLE sometable
(namestr VARCHAR(20) PRIMARY KEY)
INSERT INTO sometable VALUES ('AB-C123')
INSERT INTO sometable VALUES ('A,B,C')
SELECT namestr,
dbo.CleanChars(namestr,'A-Z 0-9')
FROM sometable
drop table sometable
drop function dbo.CleanChars
"Fraz" <Fraz@.discussions.microsoft.com> wrote in message
news:B964C72E-D1A4-4906-A105-E1D87A2F29D6@.microsoft.com...
> I am trying to retrieve the data from a table that has text datatype. I
just
> need to
> pull 5 digit numeric value from there which can later be matched with
> another table
> that has this 5 digit key. Let us assume the table name is Tab1. There are
> two
> columns col1 containing RecordId and col2 containing text data. I have
> created some dummy data to explain my needs:
> Col1 Col2
> 1001 @.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
INC.@.SOMETHING
> 1002 @.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
INC.@.SOMETHING
> 1003 @.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI INC.@.ANYTHING
> 1004 @.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM INC.@.ANYTHING
> 1005 @.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING
> 1006 @.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING
> 1007 @.:92A:CUST8@.ANYTHING
> If I use the following Query which needs to be tuned up to get the right
> resultset:
> SELECT SUBSTRING(col2, PATINDEX('%@.:97_:%', col2)+14, 5)
> from tab1
> where PATINDEX('%@.:97_:%', col2) > 0
> I get the following results: The top two results are correct but others
are
> not.
> col1 col2
> -- --
> 1001 11221
> 1002 11229
> 1003 1233@.
> 1004 333@.C
> 1005 IENT
> 1006 AME I
> I need the following resultset from the above data:
> Col1 Col2
> -- --
> 1001 11221
> 1002 11229
> 1003 11233
> 1004 11333
> 1005 22333
> Col1 Id 1006 does not have the 5 digit numeric value so it is not required
> in the
> resultset. Id 1007 does not have :97_C: so this is also not required in
the
> resultset
> too. I will appreciate your help. Thanks in advance. Fraz|||Uri: Thanks for your valuable input. This is a nice function which I am
trying to see if it can fit in my needs. If you could help little more by
showing how I can check to see the 5 digit numbers (11233) between this data
@.:97B:/XX022511233@.CLIENT. The position is always not the same. So by gettin
g
@.:97_: we can get first position and by next "@." we can get second position.
Now I know that my data is in between first and second position and by using
RIGHT function I can get the 5 right digits. Thanks again...Fraz
"Uri Dimant" wrote:

> Fraz
> Look at this example helps you
> CREATE FUNCTION dbo.CleanChars
> (@.str VARCHAR(8000), @.validchars VARCHAR(8000))
> RETURNS VARCHAR(8000)
> BEGIN
> WHILE PATINDEX('%[^' + @.validchars + ']%',@.str) > 0
> SET @.str=REPLACE(@.str, SUBSTRING(@.str ,PATINDEX('%[^' + @.validchars
+
> ']%',@.str), 1) ,'')
> RETURN @.str
> END
> GO
> CREATE TABLE sometable
> (namestr VARCHAR(20) PRIMARY KEY)
> INSERT INTO sometable VALUES ('AB-C123')
> INSERT INTO sometable VALUES ('A,B,C')
> SELECT namestr,
> dbo.CleanChars(namestr,'A-Z 0-9')
> FROM sometable
>
> drop table sometable
> drop function dbo.CleanChars
> "Fraz" <Fraz@.discussions.microsoft.com> wrote in message
> news:B964C72E-D1A4-4906-A105-E1D87A2F29D6@.microsoft.com...
> just
> INC.@.SOMETHING
> INC.@.SOMETHING
> are
> the
>
>|||Hi Fraz,
On Thu, 14 Apr 2005 06:30:05 -0700, Fraz wrote:
(snip)
>I need the following resultset from the above data:
>Col1 Col2
>-- --
>1001 11221
>1002 11229
>1003 11233
>1004 11333
>1005 22333
(snip)
Try the following (note: I added a test case to check that I return the
five digits preceding "@." AFTER the "@.:97_:" marker, not simply the
first five digits followed by "@.").
-- Set up test table and fill it with some rows
create table tab1 (col1 int not null primary key, col2 varchar(200))
go
insert into tab1
select 1001, '@.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
INC.@.SOMETHING'
union all
select 1002, '@.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
INC.@.SOMETHING'
union all
select 1003, '@.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI
INC.@.ANYTHING'
union all
select 1004, '@.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM
INC.@.ANYTHING'
union all
select 1005, '@.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING'
union all
select 1006, '@.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING'
union all
select 1007, '@.:92A:CUST8@.ANYTHING'
union all
select 1008, '@.:92A:CUST44444@.:97B:/XX022511233@.CLIENT NAME IS GHI
INC.@.ANYTHING'
go
-- Here's the code:
SELECT col1,
SUBSTRING(col2,
PATINDEX('%[0-9][0-9][0-9][0-9][0-9]@.%',
SUBSTRING(col2,
PATINDEX('%@.:97_:%', col2),
LEN(col2)))
+ PATINDEX('%@.:97_:%', col2)
- 1,
5)
FROM tab1
WHERE col2 LIKE '%@.:97_:%[0-9][0-9][0-9][0-9][0-9]@.%'
go
-- Done. Now cleanup.
drop table tab1
go
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)|||Hello Hugo,
Your code has worked excellently. Most of the 5 digit numbers were correct
except for a few records that were very long and numbers were not correct. I
have dealt with it separately. Thanks a lot for your help. Cheers... Fraz
"Hugo Kornelis" wrote:

> Hi Fraz,
> On Thu, 14 Apr 2005 06:30:05 -0700, Fraz wrote:
> (snip)
> (snip)
> Try the following (note: I added a test case to check that I return the
> five digits preceding "@." AFTER the "@.:97_:" marker, not simply the
> first five digits followed by "@.").
> -- Set up test table and fill it with some rows
> create table tab1 (col1 int not null primary key, col2 varchar(200))
> go
> insert into tab1
> select 1001, '@.:92A:CUSTOMER1@.:97D://XX022211221@.CUSTOMER NAME IS ABC
> INC.@.SOMETHING'
> union all
> select 1002, '@.:92A:CUSTOMER@.:97A://XX022311229@.CLIENT NAME IS DEF
> INC.@.SOMETHING'
> union all
> select 1003, '@.:92A:CUST4@.:97B:/XX022511233@.CLIENT NAME IS GHI
> INC.@.ANYTHING'
> union all
> select 1004, '@.:92A:CUST8@.:97C:XX022311333@.CLIENT NAME IS LKM
> INC.@.ANYTHING'
> union all
> select 1005, '@.:92A:CUST8@.:97D:22333@.CLIENT NAME IS NOP INC.@.SOMETHING'
> union all
> select 1006, '@.:92A:CUST8@.:97C:CLIENT NAME IS QRS INC.@.ANYTHING'
> union all
> select 1007, '@.:92A:CUST8@.ANYTHING'
> union all
> select 1008, '@.:92A:CUST44444@.:97B:/XX022511233@.CLIENT NAME IS GHI
> INC.@.ANYTHING'
> go
> -- Here's the code:
> SELECT col1,
> SUBSTRING(col2,
> PATINDEX('%[0-9][0-9][0-9][0-9][0-9]@.
%',
> SUBSTRING(col2,
> PATINDEX('%@.:97_:%', col2),
> LEN(col2)))
> + PATINDEX('%@.:97_:%', col2)
> - 1,
> 5)
> FROM tab1
> WHERE col2 LIKE '%@.:97_:%[0-9][0-9][0-9][0-9][0-9]@.%'
> go
>
> -- Done. Now cleanup.
> drop table tab1
> go
>
> Best, Hugo
> --
> (Remove _NO_ and _SPAM_ to get my e-mail address)
>|||On Fri, 22 Apr 2005 14:21:03 -0700, Fraz wrote:

>Hello Hugo,
>Your code has worked excellently. Most of the 5 digit numbers were correct
>except for a few records that were very long and numbers were not correct.
I
>have dealt with it separately. Thanks a lot for your help. Cheers... Fraz
Hi Fraz,
Good to hear that it worked for you. Thanks for reporting back!
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)

Password Property in ConnectionManager

I'm developing a custom manager in SSIS that has several properties defined. One property is a password string that is visible in clear text in the properties pane. I'm trying to figure out how to create a masked field in the properties pane that will mask the text and not present this in clear text. Can someone send me instructions or code samples in C# for doing this? BOL doesn't provide any information on doing this.Hi,

we're facing the same problem, but haven't found any helpful information about it.

This post doesn't really help with the issue not displaying pwds as plain text.
http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=887558&SiteID=1

Hope you guys can help.
F.|||I believe you need to implement a UITypeEditor (http://msdn2.microsoft.com/en-us/library/system.drawing.design.uitypeeditor(VS.71).aspx) to handle this type of functionality.

Password Property in ConnectionManager

I'm developing a custom manager in SSIS that has several properties defined. One property is a password string that is visible in clear text in the properties pane. I'm trying to figure out how to create a masked field in the properties pane that will mask the text and not present this in clear text. Can someone send me instructions or code samples in C# for doing this? BOL doesn't provide any information on doing this.Hi,

we're facing the same problem, but haven't found any helpful information about it.

This post doesn't really help with the issue not displaying pwds as plain text.
http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=887558&SiteID=1

Hope you guys can help.
F.

|||I believe you need to implement a UITypeEditor (http://msdn2.microsoft.com/en-us/library/system.drawing.design.uitypeeditor(VS.71).aspx) to handle this type of functionality.

Password Feild as passwordchar

Hi,

I want to put passwords in my sql table not in clear text but in password char. Pls help me

Hi, you can do it by encrypting the password text and then storing in database. Encryption can be done in asp.net and also in database (if DB engine support encryption e.g. in oracle)

|||

Thanks It works

Passing text parameters

Hello Guys,

create procedure spsCheckMsg(
@.sTyp as varchar(100),
@.tMsg as text) as
select @.tMsg = md_body from tbl_msgdef where msgname = @.sTyp

Parameters of the type text can be used in stored procedures. So I wanted to get the text data (md_body) by a select statement and pass it to the parameter @.tMsg. This code doesn't work. I always get the message "The assignment operation can't have a text datatype as argument" which refers to the select statement.

Does anyone have a solution for this?Howdy

If I have understood correctly, try :

-------------------
Create Procedure spsCheckMsg
(
@.sTyp as varchar(1000),
@.tMsg as varchar(1000)
)

AS

set @.tMsg =
( select convert(varchar(1000),md_body) from tbl_msgdef where msgname = @.sTyp )
-------------------

Cheers,

SG

Passing Text in parameter dropdown

I have a month drop down list.

In my dataset I have the code which generates month name for all months.

In my parameter list I want the functionality of the user able to select 'All' as Month name.

How can I achieve this in the query and parameter.

Code for month generation is as.

SELECT DISTINCTSUBSTRING(DATENAME(mm, T1.OPEN_TIME), 0,4) AS Month,
DATENAME(mm, T1.OPEN_TIME) AS MONTH_NAME_FULL,
DATEPART(mm, T1.OPEN_TIME) AS MONTH_NUM
FROM APPS237.Cats.dbo.Pd T1
Order By
DATEPART(mm, T1.OPEN_TIME)

Thanks,

Kiran.

You can use the UNION ALL clause to add the 'All' entry to the beginning of the table generated by your query. For example,

SELECT DISTINCT SUBSTRING(DATENAME(mm, T1.OPEN_TIME), 0,4) AS Month,
DATENAME(mm, T1.OPEN_TIME) AS MONTH_NAME_FULL,
DATEPART(mm, T1.OPEN_TIME) AS MONTH_NUM
FROM APPS237.Cats.dbo.Pd T1
UNION ALL
SELECT 'All', 'All', 0
Order By MONTH_NUM

Ian